10/26/2015, 12:56 AM
The 2sinh method is for bases larger than exp(1/2).
There are easy analogues for bases > eta.
For instance replace 2sinh with
t(x) = exp(x) - 1/2 [ exp(-x) + exp( (3 - 2e) x) ].
Notice t(x) is close to 2sinh , is bijective from R to R and has Taylor
t(x) = 0 + e x + O(x^2).
Regards
Tommy1729
There are easy analogues for bases > eta.
For instance replace 2sinh with
t(x) = exp(x) - 1/2 [ exp(-x) + exp( (3 - 2e) x) ].
Notice t(x) is close to 2sinh , is bijective from R to R and has Taylor
t(x) = 0 + e x + O(x^2).
Regards
Tommy1729

