05/26/2015, 12:28 PM
Im thinking about exp^[0.5](x + 2 pi i) - exp^[0.5](x).
I have little time.
But some ideas.
regards
tommy1729
I have little time.
But some ideas.
regards
tommy1729
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exp^[0.5](x + 2 pi i) - exp^[0.5](x)
exp^[0.5](x + 2 pi i) - exp^[0.5](x)
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exp^[0.5](x + 2 pi i) - exp^[0.5](x)
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exp^[0.5](x + 2 pi i) - exp^[0.5](x) - by tommy1729 - 05/26/2015, 12:28 PM
RE: exp^[0.5](x + 2 pi i) - exp^[0.5](x) - by MorgothV8 - 05/27/2015, 07:00 PM
RE: exp^[0.5](x + 2 pi i) - exp^[0.5](x) - by sheldonison - 12/30/2015, 04:29 PM
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