Some slog stuff

[sheldonison]

... Unless the functional equations no longer hold there.

Consider that slog(0)=-1, slog(1)=0
given the 2pi i periodicity, then
slog(2pi i)=-1; slog(1+2pi i)=0
slog(2npi i)=-1; slog(1+2npi i)=0 for any value of n

sexp is the inverse of slog. Therefore, somewhere on the sexp(z) Riemann surface, as you circle around the singularity at -2:
sexp(-1)=0; sexp(0)=1
sexp(-1)=2pi i; sexp(0)=1+2pi i
sexp(-1)=2npi i; sexp(0)=1+2npi i for any value of n