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exp^[3/2](x) > sinh^[1/2](exp(x)) ?

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exp^[3/2](x) > sinh^[1/2](exp(x)) ?
tommy1729 Offline
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#6
04/24/2015, 02:07 PM
Sheldon, that is exactly as expected.
The reason you get this result is because you used kneser instead of my 2sinh method.

If you would have used my method you should get the same result as me.
Intresting numerics through.

Regards

Tommy1729
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RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 04/24/2015, 02:07 PM

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