How it looks (i.θ)ₐ
#1
\( \\[15pt]

{e^{i.\theta}} \) is an interesting and important function, so what we get if we do the same with tetration: \( \\[15pt]

{^{i.\theta}a} \)?

I put i.x in the polynomials obtained by minimizing the error \( \\[15pt]

{\Delta^2 \,=\, (^{x}a-a^{^{x-1}a})^2} \), and drawed the imaginary vs real part:

[Image: g8O6byd.jpg?1]


These functions probably are periodical, but my polynomials only converge on -1≤x≤1, so, be careful about looking at values outside of that range.
For example, this chart is only valid in the range 0..4, for real and -4..3 for the imaginary axis.

[Image: s5jq2go.jpg?1]

This is base \( \\[15pt]

{e^{-e}} \)
[Image: HHiA8e8.jpg?1]

[Image: ccLpmS1.jpg?1]

[Image: lVPPAjA.jpg?2]

[Image: sa1kGQF.jpg?1]

[Image: 2NmY3CJ.jpg?1]

[Image: TD1wMfH.jpg?1]

This is base \( \\[15pt]

{e^{\frac{1}{e}}} \)
[Image: GNHK4Z7.jpg?1]

[Image: OeskHul.jpg?1]

This is a zoom in the curl transition
[Image: fB9vZb9.jpg?1]

[Image: gBItxkn.jpg?1]

base e, or something close, seems to delimit the transition towards the negative axis:
[Image: XKmfcQA.jpg?1]

[Image: eNJtmRN.jpg?1]

Many of these seem to be described by something like \( \\[15pt]

{^{i.x}a\,=\,c+a.cos(n.x) \,+\, i. b.sin(m.x)} \)
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Messages In This Thread
How it looks (i.θ)ₐ - by marraco - 04/18/2015, 11:20 PM
RE: How it looks (i.θ)ₐ - by sheldonison - 04/19/2015, 02:40 PM
RE: How it looks (i.θ)ₐ - by marraco - 04/19/2015, 08:40 PM
RE: How it looks (i.θ)ₐ - by sheldonison - 04/19/2015, 11:19 PM
RE: How it looks (i.θ)ₐ - by marraco - 04/20/2015, 02:35 AM
RE: How it looks (i.θ)ₐ - by Gottfried - 04/20/2015, 07:53 AM
RE: How it looks (i.θ)ₐ - by marraco - 04/21/2015, 02:34 AM
RE: How it looks (i.θ)ₐ - by marraco - 04/21/2015, 03:20 AM
RE: How it looks (i.θ)ₐ - by sheldonison - 04/21/2015, 08:23 AM
RE: How it looks (i.θ)ₐ - by marraco - 04/23/2015, 04:52 PM
RE: How it looks (i.θ)ₐ - by JmsNxn - 04/23/2015, 11:15 PM
RE: How it looks (i.θ)ₐ - by sheldonison - 04/23/2015, 11:20 PM
RE: How it looks (i.θ)ₐ - by marraco - 04/26/2015, 12:50 AM
RE: How it looks (i.θ)ₐ - by sheldonison - 04/26/2015, 05:08 AM
RE: How it looks (i.θ)ₐ - by marraco - 04/20/2015, 03:46 AM
RE: How it looks (i.θ)ₐ - by marraco - 04/23/2015, 02:21 AM
RE: How it looks (i.θ)ₐ - by marraco - 04/25/2015, 07:52 PM



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