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[2015] s(exp(d(x))) = x + 2

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[2015] s(exp(d(x))) = x + 2
tommy1729 Offline
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#2
03/26/2015, 05:35 PM
Silly me. Plug in sexp and slog and we get x + 1.

So I feel silly. However this might lead to a new method.

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Tommy1729
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[2015] s(exp(d(x))) = x + 2 - by tommy1729 - 03/26/2015, 04:34 PM
RE: [2015] s(exp(d(x))) = x + 2 - by tommy1729 - 03/26/2015, 05:35 PM

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