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[MO] Is there a tetration for infinite cardinalities? (Question in MO)

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[MO] Is there a tetration for infinite cardinalities? (Question in MO)
sheldonison Offline
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#4
12/02/2014, 02:35 PM
(12/01/2014, 11:55 PM)tommy1729 Wrote: 2^^w = the first inaccessible ordinal.

This is because 2^x = x is not accessible and 2^^w is the smallest such x.

w^^w = 2^(ln(w) 2^^w) = 2^^w = the first inaccessible ordinal.

2^^(2^^w) = the second inaccessible ordinal.

2^^(2^^w) = 2^^(w^^w) = w^^(w^^w).

Pentation

w^^^w = the w th inaccessible ordinal.

nice
- Sheldon
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RE: [MO] Is there a tetration for infinite cardinalities? (Question in MO) - by sheldonison - 12/02/2014, 02:35 PM

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