x↑↑x = -1
#18
\( \alpha_1(\text{tet}_b(z)) = z + \theta_1(z) \)

\( \alpha_2(\text{tet}_b(z)) = z + \theta_2(z) \)

I feel like this is overdetermined.

For K = 1,2,3 : let \( \theta_K(z) \) satisfy

1) \( \theta_K(z) = \theta_K(z+1) \)

2) \( \theta_K(n) = 0 \) for every integer \( n \).

3) \( \theta'_K(n) = 0 \) for every integer \( n \).

4) \( z + \theta_K(z) \) is univalent for z near the real line.

5) \( 1 + \theta'_K(z) =/= 0 \) for z near the real line.




Then

\( \alpha_1(\text{tet}_b(z + \theta_3(z) )) = T(z) \)

\( \alpha_2(\text{tet}_b(z + \theta_3(z) )) = T_2(z) \)

Where T(z) and T_2(z) are Taylor series that satisfy T_i(n) = n for all integer n and i.
( Since the LHS is a Taylor series , so is the RHS )

Let \( \alpha_2( \alpha^{[-1]}_1(z) )) = D(z) \)

Then \( D(T(z)) = T_2(z) \)

Now it seems we have more freedom.

However we require - by the above - : \( D(n) = n \)
Fortunately that seems no problems since the the two abel functions agree on integer iterates (alpha_i(b^z) = alpha_i(z)+1 ).

So we end up with :

\( \alpha_1(\text{tet}_b(z + \theta_3(z) )) = T(z) \)

such that \( T(n)=n \)

This seems to be relaxable to

\( \alpha_1(\text{tet2}_b(z)) = T(z) \)

such that \( T(n)=n \)

I suggest z is a positive real to solve the equation.

--------

now if z is a positive real :

\( \alpha_1(\text{tet2}_b(z)) - \alpha_1(\text{tet2}_b(z-1)) = T(z)-T(z-1) \)

And maybe T(z)-T(z-1) is a periodic function ?

--------

***

I notice the resemblance of

\( \alpha_1(\text{tet2}_b(z)) = T(z) \)

towards

\( \alpha_1(\text{tet}_b(z)) = z + \theta_1(z) \)

***

So when are the 5 conditions valid ??

It seems things are simplified.

But I would like to add that the radius of D(z) matters ... or that of D(T(z)).
Equations are only meaningfull within the domain of convergeance.
Maybe that is a criterion to the more general case ( apart from tetration , wheither we can agree upon 2 fixpoints ).

So it seems our attention should go to D and T perhaps rather than tet(z) in order to solve the equation.

Maybe this can be converted into carleman matrices equations.

Still thinking...

regards

tommy1729
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Messages In This Thread
x↑↑x = -1 - by KingDevyn - 05/28/2014, 04:07 AM
RE: x↑↑x = -1 - by sheldonison - 05/28/2014, 03:46 PM
RE: x↑↑x = -1 - by tommy1729 - 05/28/2014, 10:34 PM
RE: x↑↑x = -1 - by sheldonison - 05/28/2014, 11:18 PM
RE: x↑↑x = -1 - by sheldonison - 05/29/2014, 01:31 PM
RE: x↑↑x = -1 - by tommy1729 - 05/29/2014, 04:37 PM
RE: x↑↑x = -1 - by sheldonison - 05/29/2014, 08:05 PM
RE: x↑↑x = -1 - by tommy1729 - 05/29/2014, 11:15 PM
RE: x↑↑x = -1 - by sheldonison - 05/29/2014, 11:34 PM
RE: x↑↑x = -1 - by tommy1729 - 05/29/2014, 11:41 PM
RE: x↑↑x = -1 - by sheldonison - 05/29/2014, 11:44 PM
RE: x↑↑x = -1 - by tommy1729 - 05/30/2014, 09:29 PM
RE: x↑↑x = -1 - by tommy1729 - 05/31/2014, 08:31 PM
RE: x↑↑x = -1 - by tommy1729 - 05/31/2014, 09:23 PM
RE: x↑↑x = -1 - by sheldonison - 05/31/2014, 09:48 PM
RE: x↑↑x = -1 - by tommy1729 - 05/31/2014, 10:11 PM
RE: x↑↑x = -1 - by sheldonison - 06/01/2014, 01:04 AM
RE: x↑↑x = -1 - by tommy1729 - 06/02/2014, 11:17 PM
RE: x↑↑x = -1 - by sheldonison - 06/02/2014, 11:44 PM
RE: x↑↑x = -1 - by tommy1729 - 06/03/2014, 12:16 PM
RE: x↑↑x = -1 - by sheldonison - 06/03/2014, 06:09 PM
RE: x↑↑x = -1 - by tommy1729 - 06/03/2014, 08:37 PM
RE: x↑↑x = -1 - by jaydfox - 06/04/2014, 12:48 AM
RE: x↑↑x = -1 - by sheldonison - 06/04/2014, 11:43 AM
RE: x↑↑x = -1 - by tommy1729 - 06/04/2014, 12:22 PM
RE: x↑↑x = -1 - by jaydfox - 06/04/2014, 04:01 PM
RE: x↑↑x = -1 - by tommy1729 - 06/04/2014, 09:42 PM
RE: x↑↑x = -1 - by jaydfox - 06/04/2014, 11:38 PM
RE: x↑↑x = -1 - by sheldonison - 06/05/2014, 01:53 PM
RE: x↑↑x = -1 - by jaydfox - 06/05/2014, 06:51 PM
RE: x↑↑x = -1 - by sheldonison - 06/05/2014, 08:25 PM
RE: x↑↑x = -1 - by jaydfox - 06/05/2014, 10:26 PM
RE: x↑↑x = -1 - by sheldonison - 06/06/2014, 01:26 PM
RE: x↑↑x = -1 - by jaydfox - 06/06/2014, 06:17 PM
RE: x↑↑x = -1 - by tommy1729 - 06/05/2014, 10:29 PM
RE: x↑↑x = -1 - by jaydfox - 06/04/2014, 03:48 PM



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