Exact and Unique solution for base e^(1/e)
#12
Oh! Now I get it, you showed how to construct the continuous iterate of the base-\( e^{1/e} \) logarithm. I see now. Smile Good Job jaydfox, since it's a continuous iterate based on series expansion it must be related to the \( e^x - 1 \) method, and as such it is unique.

Andrew Robbins
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RE: Exact and Unique solution for base e^(1/e) - by andydude - 08/13/2007, 03:20 PM

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