Could be tetration if this integral converges
#21
(05/04/2014, 09:06 PM)JmsNxn Wrote: As a note on a similar technique you are applying Mike but trying to keep the vibe much more fractional calculus'y (since it's what I am familiar with) We will try the following function:


\( 0 < \lambda \) We want \( \lambda \) fairly small

\( \beta(w) = \sum_{n=0}^\infty \frac{w^n}{n!(^n e)} \)

We know that \( |\beta(w)| < C e^{\kappa |w|} \) for \( \kappa > 0 \) because \( \frac{1}{(^n e)} < C_\kappa \kappa^n \)

So that \( \Re(z) > 0 \).

\( F(-z) = \frac{1}{\Gamma(z)}\int_0^\infty e^{-\lambda x}\beta(-x)x^{z-1} \,dx \)

This function should be smaller then tetration at natural values.

\( F(n) = \sum_{j=0}^n \frac{n!(-\lambda)^{n-j}}{j!(n-j)!(^j e)} \)

We would get the entire expression for \( F(z) \) by Lemma 3 of my paper:

\( F(z) = \frac{1}{\Gamma(-z)}(\sum_{n=0}^\infty F(n)\frac{(-1)^n}{n!(n-z)} + \int_1^\infty e^{-\lambda x} \beta(-x)x^{z-1}\,dx) \)

Now F(z) will be susceptible to alot of the techniques I have in my belt involving fractional calculus. This Idea just popped into my head but I'm thinking working with a function like this will pull down the imaginary behaviour and pull down the real behaviour.

We also note that

\( e^{F(z) }\approx F(z+1) \). Which again will be more obvious if you look at the paper, but it basically follows because:

\( F(n) \approx (^n e) \)

So is this \( F \) supposed to approximate tetration if \( \lambda \) is small? As if so, then it doesn't seem to be working for me. If I take \( \lambda = 0.01 \) and the integral upper bound at 2000, I get \( F(1.5) \) as ~443444.33873479713260158296678612894384. Clearly, that can't be right -- it should be between \( e \) and \( e^e \) (if this is supposed to reproduce the Kneser tetrational then it should be ~5.1880309584291901006085359610758671512). It gets worse the smaller you make \( \lambda \) -- i.e. it doesn't seem to converge. Also, picking values to put in that are near-natural numbers doesn't seem to work, either.
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RE: Could be tetration if this integral converges - by mike3 - 05/05/2014, 02:11 AM

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