Is sexp(z) pseudounivalent for Re(z)

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Is sexp(z) pseudounivalent for Re(z) > 0 ?

tommy1729 Offline

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03/26/2014, 01:24 PM

Related : http://math.eretrandre.org/tetrationforu...39#pid6839

SO probably no twice a superfunction.

regards

tommy1729

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RE: Is sexp(z) pseudounivalent for Re(z) > 0 ? - by tommy1729 - 03/26/2014, 01:24 PM

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