Generalized arithmetic operator
#16
Superfunction is a multivalued function defined over a set of functions not over a set of numbers:

\( S(f)=F \) means that \( S \) takes a function \( f \) and gives a function \( S(f)=F \) calles superfunction of \( f \)

such that \( F \) satisfies

1) \( F(x+1)=f(F(x)) \)

since there are infinite solution for \( F \) (infinite superfunctions) that means that \( S(f)=F \) is multivalued and then is not a function at all and we have to put some restrictions:
using Trapmann-Kouznetsov terminology used in their paper "5+ methods..." we call \( S_u(f)=F_u \) the \( u \)-based superfunction of \( f \) the function \( F_u(x) \) that satifies two requirements

1) \( F_u(x+1)=f(F_u(x)) \)

2) \( F_u(0)=u \)


and we have

\( F_u(n)=f^{\circ n}(u) \)

In this way we obtain uniqueness over the naturals: in fact superfunction is equivalent to the "definition by recursion" that is unique .
But is not over the reals... there we need more requirments.

Obviously this is still not enough to achieve the uniqueness of \( F_u \) (iteration of \( f \)) that would mean having \( S \) to be a function over a set of functions (not multivalued).

By the way I guess that Trapmann and Kouznetsov tried to find such additionals requirments but my math level is not enough to understand it.

Anyways we have that \( S^{\circ -1} \) is a function and \( S^{\circ 1/2} \) is the half superfunction.

example :
let define \( add_b(x)=b+x \) and \( mul_b(x)=bx \) we have

\( S_0(add_b)=mul_b \) (multiplication is the 0-based superfunction of addition)

so we search for a \( S^{\circ 1/2} \) such that

\( S^{\circ 1/2}(S^{\circ 1/2}(add_b))=mul_b \)

and that if \( b[1,5]x=hyper-(1,5)_b(x) \) we should have (maybe...)

\( S^{\circ 1/2}(add_b)=hyper-(1,5)_b \)
and

\( S^{\circ 1/2}(hyper-(1,5)_b)=mul_b \)


I apologize if I did some mistakes.

Mother Law \(\sigma^+\circ 0=\sigma \circ \sigma^+ \)

\({\rm Grp}_{\rm pt} ({\rm RK}J,G)\cong \mathbb N{\rm Set}_{\rm pt} (J, \Sigma^G)\)
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Messages In This Thread
Generalized arithmetic operator - by hixidom - 03/11/2014, 03:52 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/11/2014, 03:15 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 06:24 PM
RE: Generalized arithmetic operator - by MphLee - 03/11/2014, 10:49 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 11:20 PM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 11:18 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/12/2014, 02:59 AM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 04:37 AM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 06:19 PM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 06:43 PM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:06 AM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:42 AM
RE: Generalized arithmetic operator - by hixidom - 06/11/2014, 05:10 PM

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