Generalized arithmetic operator
#14
(03/22/2014, 12:06 AM)hixidom Wrote:
Quote:what lies between tetration and pentation ?
Do we know what lies between addition and multiplication, or multiplication and exponentiation? I would be happy to know those first. I assume they would be simpler to find, but I can also imagine that they would be equally difficult to find.

Quote:Question : if we say S^[a+b](f(x)) = S^[a](S^[b](f(x)) = S^[b](S^[a](f(x))
Then what is S^[1/2](f(x)) ? Or what is S^[1/2](exp(x)) ?
I found an answer to part of your question. By that I mean I was able to find S^[1/2](exp(x)):

By definition:
\( S^{1/2}(S^{1/2}(e^x))=e^x \)

So we are trying to find some function \( f \) such that
\( f(f(x))=e^x \)

If we define \( b \) such that
\( f(x)=e^{bx} \)

then
\( f(f(x))=e^{be^{bx}}=e^x \)

\( \Rightarrow be^{bx}=x \)

\( \Rightarrow bx\cdot e^{bx}=x^2 \)

\( \Rightarrow bx=W(x^2) \), where W is the Lambert W function

\( \Rightarrow b=W(x^2)/x \)

\( \Rightarrow f(x)\equiv S^{1/2}(e^x)=e^{bx}=e^{W(x^2)} \)

There is your half-superfunction of exp(x).

Sorry for not using tex before but

By definition:
\( S^{1/2}(S^{1/2}(e^x))=S^{1/2+1/2}(e^x)=S(e^x)=sexp(x) \)

that is sufficient to see your answer is wrong ...
Sorry.

regards

tommy1729
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Messages In This Thread
Generalized arithmetic operator - by hixidom - 03/11/2014, 03:52 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/11/2014, 03:15 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 06:24 PM
RE: Generalized arithmetic operator - by MphLee - 03/11/2014, 10:49 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 11:20 PM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 11:18 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/12/2014, 02:59 AM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 04:37 AM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 06:19 PM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 06:43 PM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:06 AM
RE: Generalized arithmetic operator - by tommy1729 - 03/22/2014, 12:13 AM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:42 AM
RE: Generalized arithmetic operator - by hixidom - 06/11/2014, 05:10 PM

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