Generalized arithmetic operator
#7
I'll try to work with the equation you provided, but it will take me a while to figure it out. Thanks for the suggestion!

Regarding the relation provided:
\( a [x](\alpha + \beta) = (a[x] \alpha)[x-1](a[x] \beta) \)

It is only true when \( \alpha=\beta \), unfortunately, because
\( (a[x] \alpha)[x-1](a[x] \beta)\neq(a[x] \beta)[x-1](a[x] \alpha) \) in general.

For example (x=4):
\( (a[4]2)[3](a[4]4)\neq(a[4]4)[3](a[4]2)\leftrightarrow (a^a)^{\left ((a^a)^{(a^a)}\right )}\neq\left ((a^a)^{(a^a)}\right )^{(a^a) \)
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Messages In This Thread
Generalized arithmetic operator - by hixidom - 03/11/2014, 03:52 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/11/2014, 03:15 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 06:24 PM
RE: Generalized arithmetic operator - by MphLee - 03/11/2014, 10:49 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 11:20 PM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 11:18 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/12/2014, 02:59 AM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 04:37 AM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 06:19 PM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 06:43 PM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:06 AM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:42 AM
RE: Generalized arithmetic operator - by hixidom - 06/11/2014, 05:10 PM

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