(12/10/2012, 03:43 PM)JmsNxn Wrote: Being quick I'll write the glorious formula; \( \forall b \in \mathbb{R}\,\,;\,\, b > e^{\frac{1}{e}} \):
\( \frac{1}{^\omega b} = \sum_{N=0}^{\infty} \frac{\sum_{k=0}^{N} \frac{(-1)^{N-k}}{(N-k)!(^k b)}}{ \Gamma(\omega - N +1)} \)
considering the equation above ; if we do \( exp(-1/x) \) on both sides that should be equivalent to adding 1 to \( \omega \).
If that is not the case then the fundamental functional equation of tetration is not satisfied.
So can you confirm that doing \( exp(-1/x) \) on both sides does what it is suppose to do ?
For those confused notice \( exp(-1/x) = 1/exp(1/x) \) and \( 1/exp^{[n]}(1/x) = (1/exp(1/x))^{[n]}. \)
regards
tommy1729

