Integer tetration and convergence speed rules
#5
(12/20/2011, 11:29 PM)nuninho1980 Wrote: I understand that. Smile

2^^3 = 16
2^^4 = 65536
2^^5 = 20035... 19718 digits ...156736
2^^6 = ???... ?.??x10^19727 digits ...8736
2^^7 = ???... ?.??x10^(?.??x10^19727) digits ...48736

4^^2 = 256
4^^3 = 13407... 145 digits ...84096
4^^4 = ???... ?.??x10^153 digits ...896
4^^5 = ???... 10^^2^153 digits ...8896
4^^6 = ???... 10^^3^153 digits ...28896


Every base is characterized by this kind of convergence... (sometimes) there are only a few steps without convergence.
The asymptotic convergence speed is constant for every base (the proof is in my book)!

If you like a little more fun, you can take a look at this (in the book I have called it "sfasamento"):

[5^10^i](mod 10^30):


0- 5
1- 9765625
2- 064351090230047702789306640625
3- 927874558605253696441650390625
4- 768305384553968906402587890625
5- 423444294370710849761962890625
6- 649817370809614658355712890625
7- 838703774847090244293212890625
8- 125944280065596103668212890625
9- 648495816625654697418212890625
10- 388659619726240634918212890625
11- 255141400732100009918212890625
12- 404334210790693759918212890625
13- 333762311376631259918212890625
14- 378043317236006259918212890625
15- 820853375829756259918212890625
16- 248953961767256259918212890625
… …


0- 5
1- 9765625
2- 064351090230047702789306640625
3- 927874558605253696441650390625
4- 768305384553968906402587890625
5- 423444294370710849761962890625
6- 649817370809614658355712890625
7- 838703774847090244293212890625
8- 125944280065596103668212890625
9- 648495816625654697418212890625
10- 388659619726240634918212890625
11- 255141400732100009918212890625
12- 404334210790693759918212890625
13- 333762311376631259918212890625
14- 378043317236006259918212890625
15- 820853375829756259918212890625
16- 248953961767256259918212890625
… …

... I've discovered different kinds of convergence/pseudo-convergence... it's related to caos theory too (the underlying mathematics is group theory by Galois).

Marco
Let \(G(n)\) be a generic reverse-concatenated sequence. If \(G(1) \notin \{2, 3, 7\}\), then \(^{G(n)}G(n) \pmod {10^d}≡^{G({n+1})}G({n+1}) \pmod {10^d}\), \(\forall n \in \mathbb{N}-\{0\}\)
("La strana coda della serie n^n^...^n", p. 60).
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Messages In This Thread
RE: Integer tetration and convergence speed rules - by marcokrt - 12/21/2011, 12:03 AM

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