rumor result
#4
Dear Sheldon

do you have the coefficients for tommysexp(tommyslog(x) + k) expanded at x = 0 with respect to x and some k : 0<k<1/2 and tommyslog(0)=0 ?

or tommysexp(1)=1

thanks
Reply


Messages In This Thread
rumor result - by tommy1729 - 11/14/2011, 09:35 PM
RE: rumor result - by sheldonison - 11/15/2011, 09:22 AM
RE: rumor result - by sheldonison - 11/15/2011, 04:48 PM
RE: rumor result - by tommy1729 - 11/15/2011, 08:40 PM
RE: rumor result - by sheldonison - 11/16/2011, 11:17 AM



Users browsing this thread: 1 Guest(s)