A fundamental flaw of an operator who's super operator is addition
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A fundamental flaw of an operator who's super operator is addition
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 (09/05/2011, 11:50 PM)tommy1729 Wrote: yes that works for 2 a's ... that's my point! You cannot have an operator that works for all n a's, only at fix points Quote:Voila! this proves you cannot have an associative and commutative operator who's super operator is addition.reread my proof. the one that works for three is: \( a\,\bigtriangleup_{3^{\frac{1}{3}}}^{-1}\,b\,=\log_{3^{\frac{1}{3}}}(3^{\frac{a}{3}} + 3^{\frac{b}{3}}) \) |
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A fundamental flaw of an operator who's super operator is addition - by JmsNxn - 09/04/2011, 05:16 AM
RE: A fundamental flaw of an operator who's super operator is addition - by tommy1729 - 09/05/2011, 11:50 PM
RE: A fundamental flaw of an operator who's super operator is addition - by JmsNxn - 09/06/2011, 02:00 AM
RE: A fundamental flaw of an operator who's super operator is addition - by tetration101 - 05/15/2019, 09:49 PM
RE: A fundamental flaw of an operator who's super operator is addition - by Chenjesu - 06/23/2019, 08:19 PM
RE: A fundamental flaw of an operator who's super operator is addition - by Catullus - 06/13/2022, 11:48 PM
RE: A fundamental flaw of an operator who's super operator is addition - by MphLee - 06/16/2022, 10:33 PM
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