Precision check on [pentation.gp] SOLVED
#3
That's funny, I was just thinking about \( exp^{\pi/2} \). Naively I wanna say it's because \( \lim_{n\to\infty} ^n(e^{\pi/2}) = \lim_{n\to\infty} ^n(i^{1/i})= i \) which is what usually occurs in the self root function. However this would imply real to imaginary which isn't very pretty.

Funny that the code fails around it tho. I think there is something special about \( exp^{\pi/2} \), I'm just not sure what.
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RE: Precision check on [pentation.gp] fails? - by JmsNxn - 06/29/2011, 02:42 AM

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