(06/10/2011, 01:43 PM)sheldonison Wrote: \( \theta(z)=\sum_{n=0}^{\infty}a_n\times \e^{(2n\pi i z)} \)
Because sexp(z) here, is only an approximation, including terms with negative values of n would mean that theta(z) would not decay as z goes to \( \Im\infty \).
Ahhh! Now I understand
\( \lim_{z\to i\infty} e^{2n\pi i z} = 0 \)
you choose *the* \( \theta \) that that decays towards ioo.
Is this a uniqueness criterion for \( \theta \)?
I mean that \( \text{superf}(z+\theta(z)) \) is a real analytic superfunction and \( \theta \) decays towards \( i\infty \).
Could be, ha?
