eta as branchpoint of tetrational
#27
(06/09/2011, 02:30 PM)sheldonison Wrote:
(06/09/2011, 04:14 AM)mike3 Wrote: @sheldonison: Thanks for the coeffs. I'd like to see if I could make a color graph. What is the starting point you use for the upper regular superfunction? (i.e. the value at 0)
Hey Mike,
\( \text{Usexp}_{\sqrt{2}}(z) \) is developed from the L=4 fixed repelling point, with \( \text{Usexp}_{\sqrt{2}}(0)=5.767053253764297762019157833944 \).
\( \text{Lsexp}_{\sqrt{2}}(z) \) is developed from the L=2 fixed attracting point, with f(-1)=0, f(0)=1, f(1)=sqrt(2), and the "merger" of the two functions takes place at half the period of the LSexp=8.57i. In practice, one could literally say that for imag(z)<=8.57i Fatou(z)=Lsexp(z), and for imag(z)>=8.57i Fatou(z)=Usexp(z+k), ignoring any of the theta(z) terms, because the two functions are so very nearly identical where they merge.
- Sheldon

That is odd, since in the complex-base case you dug up that thread on, the "merger" looks to occur right along the real axis, just as it does for, say, base \( e \). This makes me suspicious if this function is really the limit of the complex-base function for \( b < \eta \). Unless, of course, the graphs are deceptive. Which is possible, given how "subtle" the curve differences are.

And half the period, or half the average of the two periods?
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Messages In This Thread
eta as branchpoint of tetrational - by mike3 - 06/02/2011, 01:55 AM
RE: eta as branchpoint of tetrational - by mike3 - 06/03/2011, 10:57 PM
RE: eta as branchpoint of tetrational - by mike3 - 06/04/2011, 09:08 AM
RE: eta as branchpoint of tetrational - by mike3 - 06/04/2011, 09:50 AM

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