f(2^x) = f(4^x + 2^(x+1) + 2) - f(4^x + 1)

[tommy1729]

not quite.

remember that an exponential function a^z = 0 has no finite solution z for a =/= 0.

it is strongly related of course.

informally speaking , we want to avoid certain fixpoints and zero's on the reals ...

tommy1729