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f(2^x) = f(4^x + 2^(x+1) + 2) - f(4^x + 1)

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f(2^x) = f(4^x + 2^(x+1) + 2) - f(4^x + 1)
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04/07/2011, 01:06 PM (This post was last modified: 04/07/2011, 01:12 PM by bo198214.)
(03/17/2011, 12:11 AM)tommy1729 Wrote: f(2^x) = f(4^x + 2^(x+1) + 2) - f(4^x + 1)

Isnt that equivalent to
f(y) = f(y^2+2y+2) - f(y^2 +1)
?
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RE: f(2^x) = f(4^x + 2^(x+1) + 2) - f(4^x + 1) - by bo198214 - 04/07/2011, 01:06 PM



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