10/12/2007, 10:18 AM
Hello Matt! Welcome to the Forum!
Well, if I got your thoughts correctly, you are thinking of:
"i" to the "i-yh" power "i" times, with "i" positive integer.
With the adopted priority rules, this means:
1 = 1#1; 2^2 = 2#2; 3^(3^3) = 3#3; 4^(4^(4^4)) = 4#4, and ... so on! Is it so? In this case, I suppose that you were thinking of:
(i,i,i) = i-tower-i = i-penta-2 !!!! Terrifically ... explosive matter. In fact, (1,1,1) = 1; (2,2,2) = 4; (3,3,3) = 3^27 = 7.62559 x 10^12, ... and so on.
Let us try and solve the tetration problems, before those concerning "pentation". However, it is a very interesting ... future dream. Unless you were thinking of "i" as the imaginary unit. In that case, I must drink a good glass of wine, before answering.
All the best.
GFR
Well, if I got your thoughts correctly, you are thinking of:
"i" to the "i-yh" power "i" times, with "i" positive integer.
With the adopted priority rules, this means:
1 = 1#1; 2^2 = 2#2; 3^(3^3) = 3#3; 4^(4^(4^4)) = 4#4, and ... so on! Is it so? In this case, I suppose that you were thinking of:
(i,i,i) = i-tower-i = i-penta-2 !!!! Terrifically ... explosive matter. In fact, (1,1,1) = 1; (2,2,2) = 4; (3,3,3) = 3^27 = 7.62559 x 10^12, ... and so on.
Let us try and solve the tetration problems, before those concerning "pentation". However, it is a very interesting ... future dream. Unless you were thinking of "i" as the imaginary unit. In that case, I must drink a good glass of wine, before answering.
All the best.
GFR