z^^z ?
#10
(01/30/2011, 06:41 PM)tommy1729 Wrote:
(01/29/2011, 11:18 PM)nuninho1980 Wrote: I edited to change from "e" to "superE" on my post #5, sorry. Wink

i dont know what your talking about actually.

There is this bifurcation base 1.6353... for the tetrational:

for b<1.6353... b[4]x has two fixpoints
for b=1.6353... b[4]x has one fixpoint
for b>1.6353... b[4]x has no fixpoint
on the positive real axis.

As you see, the bifurcation base 1.6353... of the tetrational corresponds to the bifurcation base \( e^{1/e} \) of the exponential.
(Also corresponds regarding other characterizations like the point b where b[4](b[4](b[4]...)) starts to diverge or the argument where the 4-selfroot is maximal)

The normal Euler constant e is now the one fixpoint of \( e^{1/e}[3]x \).
And the Super-Euler constant is the one (positive) fixpoint of \( 1.6353...[4]x \).
Reply


Messages In This Thread
z^^z ? - by tommy1729 - 01/18/2011, 01:44 PM
RE: z^^z ? - by tommy1729 - 01/18/2011, 09:11 PM
RE: z^^z ? - by tommy1729 - 01/18/2011, 09:49 PM
RE: z^^z ? - by bo198214 - 01/29/2011, 10:36 AM
RE: z^^z ? - by nuninho1980 - 01/29/2011, 02:05 PM
RE: z^^z ? - by tommy1729 - 01/29/2011, 03:32 PM
RE: z^^z ? - by nuninho1980 - 01/29/2011, 11:18 PM
RE: z^^z ? - by tommy1729 - 01/30/2011, 06:41 PM
RE: z^^z ? - by nuninho1980 - 01/31/2011, 01:39 PM
RE: z^^z ? - by bo198214 - 02/27/2011, 12:55 PM
RE: z^^z ? - by tommy1729 - 02/27/2011, 11:01 PM
RE: z^^z ? - by Stan - 04/05/2011, 09:26 AM
RE: z^^z ? - by tommy1729 - 04/06/2011, 03:15 PM



Users browsing this thread: 1 Guest(s)