z^^z ?

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z^^z ?

nuninho1980 Offline

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01/29/2011, 02:05 PM (This post was last modified: 01/29/2011, 11:16 PM by nuninho1980.)

(01/29/2011, 10:36 AM)bo198214 Wrote: Superlambert?

I know that - this new name is inverse of x^(superE^^x) but I don't know if this new formula is correct.

superE (= super euler) ~= 3.088532... Smile

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Messages In This Thread

z^^z ? - by tommy1729 - 01/18/2011, 01:44 PM

RE: z^^z ? - by tommy1729 - 01/18/2011, 09:11 PM

RE: z^^z ? - by tommy1729 - 01/18/2011, 09:49 PM

RE: z^^z ? - by bo198214 - 01/29/2011, 10:36 AM

RE: z^^z ? - by nuninho1980 - 01/29/2011, 02:05 PM

RE: z^^z ? - by tommy1729 - 01/29/2011, 03:32 PM

RE: z^^z ? - by nuninho1980 - 01/29/2011, 11:18 PM

RE: z^^z ? - by tommy1729 - 01/30/2011, 06:41 PM

RE: z^^z ? - by nuninho1980 - 01/31/2011, 01:39 PM

RE: z^^z ? - by bo198214 - 02/27/2011, 12:55 PM

RE: z^^z ? - by tommy1729 - 02/27/2011, 11:01 PM

RE: z^^z ? - by Stan - 04/05/2011, 09:26 AM

RE: z^^z ? - by tommy1729 - 04/06/2011, 03:15 PM

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