z^^z ?
#3
oh another thing.

let * denote complex conjugate.

at least at one branch we should have f(z) = q <=> f(z*) = q* wherever the neighbourhood of f(z) and f(z*) is holomorphic and f(z) , f(z*) are on that branch.

tommy1729
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Messages In This Thread
z^^z ? - by tommy1729 - 01/18/2011, 01:44 PM
RE: z^^z ? - by tommy1729 - 01/18/2011, 09:11 PM
RE: z^^z ? - by tommy1729 - 01/18/2011, 09:49 PM
RE: z^^z ? - by bo198214 - 01/29/2011, 10:36 AM
RE: z^^z ? - by nuninho1980 - 01/29/2011, 02:05 PM
RE: z^^z ? - by tommy1729 - 01/29/2011, 03:32 PM
RE: z^^z ? - by nuninho1980 - 01/29/2011, 11:18 PM
RE: z^^z ? - by tommy1729 - 01/30/2011, 06:41 PM
RE: z^^z ? - by nuninho1980 - 01/31/2011, 01:39 PM
RE: z^^z ? - by bo198214 - 02/27/2011, 12:55 PM
RE: z^^z ? - by tommy1729 - 02/27/2011, 11:01 PM
RE: z^^z ? - by Stan - 04/05/2011, 09:26 AM
RE: z^^z ? - by tommy1729 - 04/06/2011, 03:15 PM



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