01/15/2011, 09:29 PM
(01/15/2011, 07:06 AM)bo198214 Wrote: Just wanted to show the similarity and that it seems we can not circumvent the (measurable) Riemann mapping theorem, which gives no closed form coefficients;
??
no closed form coefficients ? Riemann mapping theorem states there is a holomorphic function !?
so we have a taylor series with its coefficients.
and although not trivial , those are computable not ?
i am either confused or disagreeing.
regards
tommy1729

