12/08/2010, 01:39 PM
(12/08/2010, 01:09 PM)sheldonison Wrote:(12/08/2010, 01:03 PM)tommy1729 Wrote: -0.36237 + iPi ??from my earlier post, sexp(-2.5)~=-0.36237+iPi. Looking at Mike's graph again, the black "zero" is at -0.696. The cutpoint for L is not even visible at 0.318+1.34i, and only becomes visible around -1+1.34i. This gives somewhat of an idea as to how mild the singularity for the half iterate at L is, with a magnitude of a little less than 1 part in 100,000 in the immediate vicinity of L itself.
where does this come from ? and what is its closed form ?
- Sheldon
then sexp(-3.5) , sexp(-4.5) , ... sexp(-(2n+1)/2)
should all have a singularity because sexp(x-1) = ln(sexp(x))
right ?

