12/08/2010, 01:03 PM
(12/08/2010, 10:16 AM)sheldonison Wrote:(12/08/2010, 02:44 AM)mike3 Wrote: Here's a graph of \( \exp^{1/2}(z) \), acquired via the Cauchy integral. Scale is from -5 to +5 on both real and imag axis:very nice. Thanks Mike! I can see the cut points at L and conj(L). Your particular cutpoint choice don't show the singularity at -0.36237+iPi. The singularity at L is somewhat less intense, in that exp^[1/2](L) is defined and equals L.
-0.36237 + iPi ??
where does this come from ? and what is its closed form ?
regards
tommy1729

