09/25/2010, 12:05 AM
a [r] b = b [r] a = exp^[r]( exp^[-r](a) + exp^[-r](b) )
now the extended distributive property is
a [r] ( b [r-1] c ) = ( a [r] b ) [r-1] ( a [r] c )
and once again tetration plays an underestimated important role
tommy1729
now the extended distributive property is
a [r] ( b [r-1] c ) = ( a [r] b ) [r-1] ( a [r] c )
and once again tetration plays an underestimated important role

tommy1729

