09/14/2010, 07:41 PM
(09/14/2010, 02:18 PM)sheldonison Wrote: Now, onto B=1.33+1.28i. The fixed repelling point is
L1 = -1.13500 - 1.98958i
with a corresponding period of -3.6051+2.4470i.
\( \text{period}(B)=2Pi*I/(L*\log(B)+\log(\log(B))) \)
its seems familiar , so forgive me for not having my day , but period of what ? a kind of sexp with base B i assume. which sexp ? computed how ?
i wanted to ask about the formula , but i think it follows when i see the answer to the above.
forgive me if i ask this again or if it has been explained before.
