08/14/2010, 03:58 AM
(08/13/2010, 06:47 AM)BenStandeven Wrote: I was hoping to include some pictures of the Julia sets of these two functions, but I don't have ready access to a program that can draw general cubic sets (such as the old Autodesk Chaos program). So I'll try again in the morning, using Fractint.
Here is the Julia set of \( z^2 - 2 \):
And here is the set for \( z^3 - 3z \):
They don't seem to be displaying on my machine, though.

