08/12/2010, 12:16 PM
similarly :
let f(z) be a non-periodic entire function.
let f(z) = f(-z)
f(z) has only 2 fixpoints ; real x and -x.
f ' (x) = 1/a and a > 1.
if lim n-> oo a^n (f^[n](z) - f^[2n](z)) exists and is entire then this is the superfunction matching both fixpoints.
regards
tommy1729
let f(z) be a non-periodic entire function.
let f(z) = f(-z)
f(z) has only 2 fixpoints ; real x and -x.
f ' (x) = 1/a and a > 1.
if lim n-> oo a^n (f^[n](z) - f^[2n](z)) exists and is entire then this is the superfunction matching both fixpoints.
regards
tommy1729