fibonacci like
#11
(07/17/2010, 08:45 AM)mike3 Wrote:
(07/17/2010, 07:02 AM)Gottfried Wrote: I had tried it up to
Quote:\( e^{(1+i)u} - e^u = -1 \)
but gave up then...

What's the problem?

No - there is no problem. It only looked not easy enough for an idle afternoon so I didn't try to proceed further on my own. Your arguments make it actually easy to proceed and even more: you've done some nice graphs... So your msg was a nice and interesting contribution!

Gottfried
Gottfried Helms, Kassel
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Messages In This Thread
fibonacci like - by tommy1729 - 07/10/2010, 12:27 PM
RE: fibonacci like - by tommy1729 - 07/14/2010, 01:55 PM
RE: fibonacci like - by bo198214 - 07/15/2010, 02:29 AM
RE: fibonacci like - by Gottfried - 07/15/2010, 08:56 AM
RE: fibonacci like - by tommy1729 - 07/15/2010, 12:06 PM
RE: fibonacci like - by bo198214 - 07/16/2010, 07:03 AM
RE: fibonacci like - by tommy1729 - 07/16/2010, 12:27 PM
RE: fibonacci like - by bo198214 - 07/18/2010, 07:44 AM
RE: fibonacci like - by mike3 - 07/17/2010, 01:50 AM
RE: fibonacci like - by Gottfried - 07/17/2010, 07:02 AM
RE: fibonacci like - by mike3 - 07/17/2010, 08:45 AM
RE: fibonacci like - by Gottfried - 07/17/2010, 10:31 AM
RE: fibonacci like - by tommy1729 - 07/17/2010, 08:03 PM
RE: fibonacci like - by mike3 - 07/18/2010, 01:47 AM
RE: fibonacci like - by tommy1729 - 07/18/2010, 09:54 PM

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