using sinh(x) ?

[tommy1729]

also worth mentioning i think :

let the base be a^(1/b) > sqrt(e) so that we can compute

the superfunction of f(x) = a^(1/b)^x with my method.

then consider t(x) = b(x + c)

and its inverse m(x) = x/b - c

m(f(t(x))) = m(a^(x+c)) = (1/b) a^(x+c) - c = (a^c / b) a^x - c

if a , b and c are chosen such that (a^c / b) a^x - c > x

we can compute the superfunction of (a^c / b) a^x - c by computing m(f^[z](t(x))).

regards

tommy1729