Regular "pentation"?
#3
(05/01/2010, 03:21 PM)tommy1729 Wrote: dear mike

the regular interval that you seek has been computed by andy.

its somewhere here on this forum.

Lazy boy!
Andrew gave a rough overview of the behavior of the higher operations here.

Due to the fact that \( \operatorname{sexp}_b(x)\to -\infty \) (below identity) for \( x\to -2 \) and \( \operatorname{sexp}_b(0)=1 \) (above identity), tetration always (for every base) has a lower fixed point (I guess this is true for every even rank), which can be used for regular iteration giving a pentation (or the odd rank above).


Interesting question would indeed be for which bases pentation has a lower fixed point (but indeed I think this was computed already on the forum, perhaps do a search for pentation).
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Messages In This Thread
Regular "pentation"? - by mike3 - 05/01/2010, 11:56 AM
RE: Regular "pentation"? - by tommy1729 - 05/01/2010, 03:21 PM
RE: Regular "pentation"? - by bo198214 - 05/01/2010, 08:54 PM
RE: Regular "pentation"? - by mike3 - 05/02/2010, 12:07 AM
RE: Regular "pentation"? - by andydude - 05/02/2010, 09:12 AM
RE: Regular "pentation"? - by Base-Acid Tetration - 05/02/2010, 11:29 PM
RE: Regular "pentation"? - by andydude - 05/03/2010, 02:54 AM
RE: Regular "pentation"? - by mike3 - 05/03/2010, 03:27 AM
RE: Regular "pentation"? - by andydude - 05/07/2010, 03:10 AM
RE: Regular "pentation"? - by andydude - 05/07/2010, 03:17 AM
RE: Regular "pentation"? - by mike3 - 05/07/2010, 06:07 AM

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