09/10/2007, 05:32 PM
jaydfox Wrote:If we call the fixed point x, then here's a look at the coefficients a_k of Andrew's slog, divided by the real part of x^(k+1), multiplied by k (to effect the derivative), and multiplied by abs(x^2).What fixed point?
Quote:With a few exceptions in the first handful of terms, the values seem to be converging on 1.0579. As it turns out, \( {\Large x}^{-1.057939991157 i} \) is equal to \( \Large{x}^{1.057939991157*{\large \left|\frac{x^{\tiny -i}}{x}\right|} \). In other words, if you start at a point very near the fixed point, then 4.44695 real iterations and -1.05794 imaginary iterations will get you to the same point.What?
