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Road testing Ansus' continuum product formula

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Road testing Ansus' continuum product formula
mike3 Offline
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09/15/2009, 10:34 PM (This post was last modified: 09/15/2009, 10:35 PM by mike3.)
However that doesn't really seem to say how you obtain that numerical value for the derivative at 0, which is what I was asking about. Where does that come from? I.e. how did you come up with that number 1.0917... for base e? What would it be for base 2? For base 0.04 (should be some complex number)?
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Messages In This Thread
the summation problem, references - by bo198214 - 09/21/2009, 02:29 PM
RE: the summation problem, references - by mike3 - 09/21/2009, 08:06 PM
RE: the summation problem, references - by mike3 - 09/22/2009, 05:27 AM
RE: the summation problem, references - by mike3 - 09/22/2009, 05:30 AM

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