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Personal Scratchpad

bo198214 Offline

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#11

09/02/2007, 08:42 PM

jaydfox Wrote:\(
\begin{eqnarray}
\lim_{h \to 0^{+}} \frac{\mathcal{E}^{'}(z+h)-\mathcal{E}^{'}(z)}{h} & > & 0 \\
\\[10pt]

\\

\lim_{h \to 0^{+}} \mathcal{E}^{'}(z+h) & > & \mathcal{E}^{'}(z) \\
\end{eqnarray}
\)

I am not sure whether your final result is true. However the above reasoning is formally wrong.
As \( \lim_{h\downarrow 0} f(z+h)=f(z) \) for a continuous function \( f \).

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Personal Scratchpad - by jaydfox - 09/01/2007, 04:18 PM

RE: Personal Scratchpad - by jaydfox - 09/01/2007, 04:19 PM

RE: Personal Scratchpad - by jaydfox - 09/01/2007, 05:05 PM

RE: Personal Scratchpad - by bo198214 - 09/01/2007, 06:04 PM

RE: Personal Scratchpad - by jaydfox - 09/01/2007, 10:28 PM

RE: Personal Scratchpad - by jaydfox - 09/01/2007, 10:36 PM

RE: Personal Scratchpad - by jaydfox - 09/01/2007, 08:25 PM

RE: Personal Scratchpad - by jaydfox - 09/02/2007, 08:10 PM

RE: Personal Scratchpad - by jaydfox - 09/02/2007, 08:11 PM