07/05/2009, 03:32 PM
Sorry for putting this in the wrong section BTW.
Im only 14 so I dont understand all this advanced mathematics, but let me ask you this, is x^^0 x? Multiplication is as follows:
X*5=X+X+X+X+X
X*4=X+X+X+X
X*3=X+X+X
X*2=X+X
X*1=X
X*0=X-X
X*-1=X-X-X
X*-2=X-X-X-X
X*-3=X-X-X-X-X
X*-4=X-X-X-X-X-X
X*-5=X-X-X-X-X-X-X
And then going up to hyper 3 it becomes:
X^5=X*X*X*X*X
X^4=X*X*X*X
X^3=X*X*X
X^2=X*X
X^1=X
X^0=X/X
X^-1=X/X/X
X^-2=X/X/X/X
X^-3=X/X/X/X/X
X^-4=X/X/X/X/X/X
X^-5=X/X/X/X/X/X/X
So, therefore hyper 4 should be:
X^^5=X^X^X^X^X
X^^4=X^X^X^X
X^^3=X^X^X
X^^2=X^X
X^^1=X
X^^0=X√X
X^^-1=X√X√X
X^^-2=X√X√X√X
X^^-3=X√X√X√X√X
X^^-4=X√X√X√X√X√X
X^^-5=X√X√X√X√X√X√X
Im only 14 so I dont understand all this advanced mathematics, but let me ask you this, is x^^0 x? Multiplication is as follows:
X*5=X+X+X+X+X
X*4=X+X+X+X
X*3=X+X+X
X*2=X+X
X*1=X
X*0=X-X
X*-1=X-X-X
X*-2=X-X-X-X
X*-3=X-X-X-X-X
X*-4=X-X-X-X-X-X
X*-5=X-X-X-X-X-X-X
And then going up to hyper 3 it becomes:
X^5=X*X*X*X*X
X^4=X*X*X*X
X^3=X*X*X
X^2=X*X
X^1=X
X^0=X/X
X^-1=X/X/X
X^-2=X/X/X/X
X^-3=X/X/X/X/X
X^-4=X/X/X/X/X/X
X^-5=X/X/X/X/X/X/X
So, therefore hyper 4 should be:
X^^5=X^X^X^X^X
X^^4=X^X^X^X
X^^3=X^X^X
X^^2=X^X
X^^1=X
X^^0=X√X
X^^-1=X√X√X
X^^-2=X√X√X√X
X^^-3=X√X√X√X√X
X^^-4=X√X√X√X√X√X
X^^-5=X√X√X√X√X√X√X

