05/04/2009, 09:06 PM
(This post was last modified: 05/04/2009, 09:10 PM by Base-Acid Tetration.)
(05/04/2009, 09:01 PM)bo198214 Wrote:(05/04/2009, 08:57 PM)Tetratophile Wrote: bo, you needed to see my explanation.
1. Evaluate g(x) at c first.
2. Hyper-n-iterate f to the OUTPUT of Step 1.
3. Evaluate the resulting function at c.
For n=1 (iteration), to evaluate this expression at any given natural x=c:
1. Evaluate g(x) at c first.
2. Iterate f to the OUTPUT of Step 1.
3. Evaluate the resulting function at c.
The set of all ordered pairs resulting from this evaluation is {(x, [f It_1 g(x)] (x))}.
I know, but I dont know what you want to say with that *questioningly look*.
We agree on the meaning, the question is more how to write it down properly.
Ok, I now see that you were only trying to clarify my notation. I would agree that your notation emphasizes that hyper-iterations are actually: function * OUTPUT of a function -> function.
tongue in cheek edit: all this editing posts only to see it was too late biz, i know... wastes such a h**k of time...

