A nice series for b^^h , base sqrt(2), by diagonalization

[andydude]

then the limit can be given as
\( \lim_{\delta \to 0+} b[4](\delta -2) - \log_b(\delta)=\log_b\left(\frac{\text{sexp}'(0)}{\ln(b)}\right) \)

You know, at first I was confused, because this formula implies that
\( \lim_{z\to -2^{+}}(\text{sexp}(z) - \ln(z+2)) = -2.4327187635454386 \)
but the Cz page gives
\( \lim_{z\to 0^{+}}(\text{sexp}(z) - \ln(z+2)) = 0.30685281944005469 \)
but then I realized the point was different

Andrew Robbins