03/13/2009, 06:14 PM
Gottfried Wrote:Ansus Wrote:For the base e sexp'(-1)=sexp'(0) so slog'(0)=slog'(1), can you verify this for your formula?
Don't think so. I've not even completed the full reformulation of Andrew's formula...
Gottfried
Perhaps one should add that the superlogarithm for base \( b>e^{1/e} \) by this formula is not a real function, i.e. has complex values for real arguments.
While the superlogarithm with Andrew's original formula is a real function.
