Taylor series of upx function
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Taylor series of upx function
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02/20/2009, 11:44 AM
Ansus Wrote:You can compare your solution with a new analytic solution suggested here: Dmitrii uses two distinct methods for \( b>e^{1/e} \) and for \( b<e^{1/e} \). I think he uses regular iteration for \( b<e^{1/e} \) so for \( b=\sqrt{2} \) your graphs should be equal, considering what I replied to your newton method. |
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Taylor series of upx function - by Zagreus - 09/07/2008, 10:56 AM
RE: Taylor series of upx function - by bo198214 - 09/10/2008, 01:56 PM
RE: Taylor series of upx function - by andydude - 10/23/2008, 10:16 PM
RE: Taylor series of upx function - by Kouznetsov - 11/16/2008, 01:40 PM
RE: Taylor series of upx function - by bo198214 - 11/16/2008, 07:17 PM
RE: Taylor series of upx function - by sheldonison - 11/17/2008, 12:21 AM
RE: Taylor series of upx function - by Kouznetsov - 11/17/2008, 04:11 AM
RE: Taylor series of upx function - by bo198214 - 11/18/2008, 11:49 AM
RE: Taylor series of upx function - by sheldonison - 03/05/2009, 06:48 PM
RE: Taylor series of upx function - by Kouznetsov - 12/02/2008, 12:03 PM
RE: Taylor series of upx function - by sheldonison - 12/03/2008, 09:11 PM
RE: Taylor series of upx function - by Kouznetsov - 12/05/2008, 12:30 AM
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