f( f(x) ) = exp(x) solved ! ! !
#26
[/quote]

Well, because \( F(x) = w^x - 1 \) and \( G(x) = w^{x/w} = e^x \) are topologically conjugate (where \( w = -W(-1) \)), I kind of skipped a step and thought of F (which has a fixed point of 0) and G (which has a fixed point of w) at the same time.

Also, I do understand the general idea of tommy's method, to make a function with a fixed point at 0, as a limit of a function with a fixed point not at zero. It makes sense. I just need to sit down at look over the math for a week or so, to convince myself that it all works, and that it gives new insight to the problem.

Andrew Robbins
[/quote]

ive been absent for a few days , but im thinking ( working ? ) on related ideas.

such as convergeance acceleration.

or a zero at other points then 0.

i dont think my fixed point at 0 gives a convex solution to tetration ...

i will post a conjecture soon.

regards

tommy1729
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Messages In This Thread
f( f(x) ) = exp(x) solved ! ! ! - by tommy1729 - 02/05/2009, 12:09 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/05/2009, 09:17 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 03:22 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/06/2009, 06:02 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/07/2009, 12:37 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 12:15 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by bo198214 - 02/08/2009, 10:08 PM
RE: f( f(x) ) = exp(x) solved ! ! ! - by andydude - 02/14/2009, 04:18 AM
RE: f( f(x) ) = exp(x) solved ! ! ! - by tommy1729 - 02/17/2009, 12:30 AM

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