Unique Holomorphic Super Logarithm
#2
Your figure looks similar to Fig.3 by Kneser.
bo198214 Wrote:We call a function \( \text{slog} \) defined on the domain \( H \) a super logarithm iff \( \text{sexp}(\text{slog}(z))=z \) for each \( z\in H \) (but not necessarily \( \text{slog}(\text{sexp}(z)) \) for each \( z\in\text{slog}(H) \)).
Why "non necessarily"?
\( H=\mathrm{sexp}(D) \) ?
\( D=\mathrm{slog}(H) \) ?
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Messages In This Thread
Unique Holomorphic Super Logarithm - by bo198214 - 11/18/2008, 06:18 PM
RE: Unique Holomorphic Super Logarithm - by Kouznetsov - 11/19/2008, 03:24 AM

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