Computing Andrew's slog solution
#15
The more I think about it, the more I realize that the radius should act like a normal radius (i.e., be a single circle). The fact that the series seems to converge well outside the radius is an artifact of the truncation of the series. In other words, the partial sums act divergently, but when we reach the last term, the series "magically" converges over an extended range around z=1.

However, the infinite series (if it exists, which I agree with Andrew seems likely) has no last term, so this won't happen, not in a traditional sense, anyway. Therefore, we should look at the behavior of the penultimate partial sum of any particular truncation to approximate the true radius of convergence.
~ Jay Daniel Fox
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Messages In This Thread
Computing Andrew's slog solution - by jaydfox - 08/21/2007, 04:27 PM
RE: Computing Andrew's slog solution - by jaydfox - 08/21/2007, 04:41 PM
RE: Computing Andrew's slog solution - by jaydfox - 08/22/2007, 04:27 AM
RE: Computing Andrew's slog solution - by jaydfox - 08/22/2007, 10:41 AM
RE: Computing Andrew's slog solution - by jaydfox - 08/22/2007, 04:00 PM
RE: Computing Andrew's slog solution - by jaydfox - 08/22/2007, 04:06 PM
RE: Computing Andrew's slog solution - by jaydfox - 08/23/2007, 07:27 AM
RE: Computing Andrew's slog solution - by jaydfox - 08/23/2007, 04:43 PM
RE: Computing Andrew's slog solution - by jaydfox - 08/23/2007, 04:47 PM
RE: Computing Andrew's slog solution - by jaydfox - 08/24/2007, 07:07 AM
RE: Computing Andrew's slog solution - by jaydfox - 08/24/2007, 07:48 AM
RE: Computing Andrew's slog solution - by jaydfox - 08/24/2007, 03:20 PM

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