05/24/2008, 09:04 AM
Ivars Wrote:\( \phi(f^{\circ I}(x))=\phi(x)+I \).
If we turn it upside down, we can may be use the result of t iterations of a function to define what COUNTING with t (e.g. t=I) means.
Ivars, we do exactly that! How do you think we compute \( b[4](I*t) \)?
I wrote it already
bo198214 Wrote:The equation \( f^{\circ n}(x)=\phi^{\circ-1}(\phi(x)+n) \) is of course easily applicable to complex \( n \) nothing needs to be changed just keep the law for complex \( n \) too. E.g.in this previous post
\( f^{\circ I}(z)=\phi^{\circ -1}(\phi(z)+I) \).
But btw this give no clue about what x[I]y is.
