But to see this oscillating behaviour between I and -I you dont need to do numerical computations, as you already mentioned:
\( b^I=(I^I)^I=I^{-1}=-I \)
and the next step is to look at
\( b^{-I}=(I^I)^{-I}=I^1=I \)
Hence this oscillating behaviour for base \( b=I^I \).
And yes this is one non-converging case.
\( b^I=(I^I)^I=I^{-1}=-I \)
and the next step is to look at
\( b^{-I}=(I^I)^{-I}=I^1=I \)
Hence this oscillating behaviour for base \( b=I^I \).
And yes this is one non-converging case.
